Javascript删除字符串中所有开头和结尾的垃圾字符

Question

I have strings like

"&% , USEFUL DATA ^$^@&#!*, USEFUL DATA *%@^#,,,   "

Need it cleaned like:

"USEFUL DATA   ^$^@&#!*,  USEFUL DATA"

Do we have any standard library function in Javascript to do that (We have it in python)?

Ex: trim(str, "!@#$%^^&*(), ")

Answer 1

You can use:

str = str.replace(/^\W+|\W+$/g, "");

\\W will match all the non-word characters.

RegEx Demo

To remove specific character use character class:

str = str.replace(/^[@#$%^&*(), ]+|[@#$%^&*(), ]+$/g, "");

Answer 2

You can use a regex replace :

 var s = "&% , USEFUL DATA ^$^@&#!*, USEFUL DATA *%@^#,,, "; document.write(s.replace(/^\\W+|\\W+$/g, '') + "<br/>"); // or document.write(s.replace(/^[^\\w]+|[^\\w]+$/g, '')); 

The pattern ^\\W+|\\W+$ will remove all "special" characters from both beginning and end of the string. Note that \\W matches every character that is not in the [A-Za-z0-9_] class, and \\w matches those characters. [^\\w] is a negated character class where ^ means not , and then you can add more characters/shorthand classes that you want to keep.