如何在openURL swift中捕获错误的URL

Question

If my url has a space at the end it crashes with EXC_BAD_INSTRUCTION.

I thought canOpenURL would trap for a bad URL but it doesn't.

if let strurl = cell.url{
    if (UIApplication.sharedApplication().canOpenURL(NSURL(string:strurl)!)) {
        UIApplication.sharedApplication().openURL(NSURL(string:strurl)!);
    }
}

In my case a URL with an extra space at the end crashes it. I can trim white space, but what about anything else? Is there a proper way to trap for this error?

Answer 1

You are force unwrapping NSURL which causes the app to crash if it happens to be nil . To check the validity of the URL you should be using if let on the URL itself as well.

if let strurl = cell.url,
   let url = NSURL(string: strurl) {
      if (UIApplication.sharedApplication().canOpenURL(url) {
          UIApplication.sharedApplication().openURL(url)
      }
}