如何从ajax请求中获取返回的URL

Question

i'm trying to get only the returned URL from ajax request

like this

 $.ajax({
                    type: "GET",
                    dataType : "jsonp",
                    async: false,
                    url: $('#FaceBookProfileLink').attr('href'),

                    success: function(response) {
                        console.log(response);
                    },
                    error: function (jqXHR, textStatus, errorThrown) {
                        console.log(jqXHR);
                        console.log(textStatus);
                        console.log(errorThrown);
                    }
                });

but i can't.

the returned URL showing in the console as js file but i can't get it

please any help and many thanks in advance.

Answer 1

当您使用'GET'方法时，请使用$ _GET []检索它们，即：

echo $_GET['code']