i'm trying to get only the returned URL from ajax request
like this
$.ajax({
type: "GET",
dataType : "jsonp",
async: false,
url: $('#FaceBookProfileLink').attr('href'),
success: function(response) {
console.log(response);
},
error: function (jqXHR, textStatus, errorThrown) {
console.log(jqXHR);
console.log(textStatus);
console.log(errorThrown);
}
});
but i can't.
the returned URL showing in the console as js file but i can't get it
please any help and many thanks in advance.
当您使用'GET'方法时,请使用$ _GET []检索它们,即:
echo $_GET['code']
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