在C ++中使用数组的奇怪输出

Question

I am working on one of the programs using arrays. What I want is to..add the elements of the char array and give the output. Here's the code:

#include<iostream>
#include<string.h>

using namespace std;
int main()
{
char number[8];
int in , i = 0 , square = 0;
cin>>number;
while(1){
    if(i != strlen(number)){
    square = (number[i]) + square;
    cout<<square<<"\n";

    }
    else{
        break;
    }
    i++;
}
cout<<square - 48*(strlen(number));
return 0;
}

the strange thing is that the output is 48 x (the number of digits of input) more than the original input, that is why I have subtracted that part from the output. Why this happens?

Answer 1

number[i] is a character, but you are treating it as if it was an integer. '0' (a character) does not equal 0 (an integer), '1' does not equal 1 etc. The simple way to convert a decimal digit character to an integer is to subtract '0' from it. Like this

square = (number[i] - '0') + square;

'0' - '0' does equal 0 , '1' - '0' does equal 1 , etc.