排序nsarray最长到最短的字符串

Question

I have a NSArray i want to sort by longest string to shortest string

For example-

 NSArray *strings=[NSArray arrayWithObjects:@"as12332", @"ol", @"st", @"br", @"gj", @"wr", @"qwos", nil];

i want result like-

@"as12332",@"qwos", @"ol", @"st", @"br", @"gj", @"wr".

sort by string length.

Answer 1

You can use this code to implement what you're trying to achieve:

NSArray *strings=[NSArray arrayWithObjects:@"as12332", @"ol", @"st", @"br", @"gj", @"wr", @"qwos", nil];
NSArray *sortedArray;
sortedArray = [strings sortedArrayUsingComparator:^NSComparisonResult(NSString *first, NSString *second)
{
    return [self compareLengthOf:first withLengthOf:second];
}];

sortedArray will contain the elements, sorted by length.

The implementation for the comparison method is:

    - (NSComparisonResult)compareLengthOf:(NSString *)firstStr withLengthOf:(NSString *)secondStr
{
    if ([firstStr length] > [secondStr length])
        return NSOrderedAscending;
    else if ([firstStr length] < [secondStr length])
        return NSOrderedDescending;
    else
        return NSOrderedSame;
}

You can add more logic to the comparisson method, if you would like to have a secondary sort based on alphabetical order, for example.