如何使用php获取图像标题

Question

I'm using PHP to put all the images in a given folder into a slideshow. This works fine in the following code:

<?php
//get all image files with a .jpg extension.
$images = glob("" . $directory . "*.jpg");

$imgs = array();
// create array
foreach($images as $image){ $imgs[] = "$image"; }

/****** Display Images ******/
foreach ($imgs as $img) {
    //I would like to get the image title here, to put in the echo below    
    echo "<div><img src='$img' border='0' width=\"100%\" height=\"100%\"/ /></div>"; 
    }
?>

This all goes quite easy, but since I would now also like to add the Titles of the pictures as captions, I need to extract/get this information from the image.

I'm thinking I can get it with something along the lines of the function exif_read_data , but I'm not quite sure how to get the title and not all the meta data . . .

---

With a little help from the smart people using stackoverflow, this is the final and functional result, as seen in my answer below as well and again, made with bits and pieces from several answers.

<?php
/*
This script will print the image files in a given folder, along with their image description (title in windows file explorer).
*/

// Set the directory where the files reside
$directory = $GLOBALS['directory'];

//get all image files with a .jpg extension.
$imagenpath = glob("" . $directory . "*.jpg");

$imgs = array();
// create array
foreach($imagenpath as $image){ $imgs[] = "$image"; }

// Print each image file with the ImageDescription (the title/caption) in the ALT field
foreach ($imgs as $img) {
    $exif_data = exif_read_data($img, 'IFD0');
    $exif_description = "";
    if (!empty($exif_data['ImageDescription'])) 
        $exif_description = $exif_data['ImageDescription'];

    echo "<div><img src='$img' alt='$exif_description' border='0' width=\"100%\" height=\"100%\"/ /></div>";
}
?>

Answer 1

thats everything that can be done, because most pictures are not supported with this function, though, you are doing it wrong because the error that you are getting is because the file is not found, the error you get when the file is found and is not supported is this:

Warning: exif_read_data(file.png): File not supported in /path/to/file/file.php on line x

and its because you single quoted the variable in

    $exif_data = exif_read_data($img, 'IFD0');

the code could be less characters, this is my solution:

<?php
/*
This script will print the image files in a given folder, along with their image description (title in windows file explorer).
*/

// Set the directory where the files reside
$directory = $GLOBALS['directory'];

//get all image files with a .jpg extension.
$imgs = glob($directory . "*.jpg");

// Print each image file with the ImageDescription (the title/caption) in the ALT field
foreach ($imgs as $img) {
    $exif_data = exif_read_data($img, 'IFD0');
    if (!empty($exif_data['ImageDescription'])) 
        $exif_description = $exif_data['ImageDescription'];

    echo "<div><img src=\"$img\" alt=\"$exif_description\" border=\"0\" width=\"100%\" height=\"100%\"/ /></div>";
}
?>

Answer 2

Try this :-

foreach (glob("*.jpg") as $filename) {
    $name = basename($filename, '.jpg');
    echo "<div><img src='$filename' title='$name' alt='$name' border='0' width=\"100%\" height=\"100%\"/ /></div>";
}

Answer 3

To solve the problem, I basically used the Windows file browser, selected the image file and entered the text in the document comments section.
Then I printed the $exif_data as suggested above by @RamRaider and found out this text ends up in the ImageDescription of the file.

Once I nailed down the errors in my script, along with help from @Abdallah Samman, there wasn't much to it anymore!

Thank you everyone...

The following works beautifully:

<?php
/*
This script will print the image files in a given folder, along with their image description.
*/

// Set the directory where the files reside
$directory = $GLOBALS['directory'];

//get all image files with a .jpg extension.
$imagenpath = glob("" . $directory . "*.jpg");

$imgs = array();
// create array
foreach($imagenpath as $image){ $imgs[] = "$image"; }

// Print each image file with the ImageDescription (the caption) in the ALT field
foreach ($imgs as $img) {
    $exif_data = exif_read_data($img, 'IFD0');
    $exif_description = "";
    if (!empty($exif_data['ImageDescription'])) 
        $exif_description = $exif_data['ImageDescription'];

    echo "<div><img src='$img' alt='$exif_description' border='0' width=\"100%\" height=\"100%\"/ /></div>";
}
?>