将Gunzip输出重定向到python脚本

Question

I want to gunzip a series of files and then redirect the output to my python script. The python script gets one argument as the input. I wrote the following command:

for i in $(ls test5/*/*gz); do gunzip -c $i | python script.py ; done

But it gives me the following error:

Traceback (most recent call last):
  File "./fqtofa.py", line 7, in <module>
    inFile = sys.argv[1]
IndexError: list index out of range

I wonder why it can't read from the gunzip output.

Answer 1

sys.argv is for command-line arguments. You're not passing any of those, you're piping it in via stdin. So you need to read from sys.stdin .