对两个捕获组求和

Question

I need get two values from a string and sum them.

var text = 'SOC 01 672 1.653.806,08 18.512,98 1.667.621,57 2.647,38 07 23 12.965,11 0,00 12.965,11 0,00 13 5 10.517,81 0,00 10.517,81 0,00';
var reg  = new RegExp('SOC 01' +  '\\b.*?(?:\\d\\S*\\s+){3}(\\d\\S*)', 'i');
var reg2 = new RegExp('SOC 01' +  '\\b.*?(?:\\d\\S*\\s+){7}(\\d\\S*)', 'i');
var match = reg.exec(text);
var match2 = reg2.exec(text);

Output:

match[1] -> '1.667.621.57'
match2[1] -> '12.965.11'

(OBS: If you try run in the console the last number will have a comma, but in my node.js environment is a dot.)

I would like to know if i can create just one regex with two groups and sum them together.

The total should be 1.691.104,49

I was trying to sum like this:

(+match[1]) + (+match2[1])

output: NaN

Thanks.

Answer 1

You're going to have to do something like:

Number(match[1].replace(/[\.,]/g, ''))

To strip out the . s and , s before summing the numbers.

If you need to get the number back into the same format, you can do something like this:

var total = Number(match[1].replace(/[\.,]/g, '')) + Number(match2[1].replace(/[\.,]/g, ''));

var result = String(total);
result = result.replace(/(?=\d{2}$)/, ',');
result = result.replace(/\B(?=(\d{3})+(?!\d))/g, '.');

Which produces 1.680.586,68 . I have the same question as stribizhev about how you are doing the summing.

Here is the fiddle for the above example: https://jsfiddle.net/qw700fq9/

Here is the updated fiddle - cleaned it up a bit: https://jsfiddle.net/rdu15ds3/

Also, adding the decimals back in was based on the answers to this question: How to print a number with commas as thousands separators in JavaScript

Answer 2

The regex is returning a string. You need to convert them to numbers before adding them.

function toNumber(n){
    return parseFloat(n.replace(/./g,'').replace.(/,/g,'.'));
}

toNumber(+match[1]) + toNumber(+match2[1]);