删除除子目录中最新的10个文件外的所有文件

Question

I have some BackUp-Files from machines which store their Backup in different folders. Additionally the files are not created at the same time (Machine 1: every sunday, Machine 2: every first monday of the month, etc.).

I need to keep the latest 10 files in each folder and delete all the others. Because of the different backup-intervals I can't just delete all files older than x days.

The folder-structure is like this:

./<SystemType>/<FQDN_Machine1>/backup_2015_09_08_02_00_00.zip
./<SystemType>/<FQDN_Machine2>/backup_2015_09_01_14_00_00.zip

Answer 1

IFS='
'
for i in dir/*; do
    ls -d1t $i/* | head -n-10
done | xargs rm

List all subdirs excluding latest ten and send it by xargs to rm .

Answer 2

This is my solution:

#!/bin/bash

cat find ./ -type f | while IFS= read -r line
do
  find "$line" -type f | head -n -10 | while read file
  do
    rm -f "$file"
  done
done