[英]delete all files except a pattern list file
I need to delete all the files in the current directory except a list of patterns that are described in a whitelist file ( delete_whitelist.txt ) like this:我需要删除当前目录中的所有文件,除了白名单文件( delete_whitelist.txt )中描述的模式列表,如下所示:
(.*)dir1(/)?
(.*)dir2(/)?
(.*)dir2/ser1(/)?(.*)
(.*)dir2/ser2(/)?(.*)
(.*)dir2/ser3(/)?(.*)
(.*)dir2/ser4(/)?(.*)
(.*)dir2/ser5(/)?(.*)
How can I perform this in one bash line?如何在一个 bash 行中执行此操作?
Any bash script can fit on one line:任何 bash 脚本都可以放在一行中:
find . -type f -print0 | grep -EzZvf delete_whitelist.txt | xargs -0 printf '%s\n'
Check the output and then, if it's OK:检查输出,然后,如果没问题:
find . -type f -print0 | grep -EzZvf delete_whitelist.txt | xargs -0 rm
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