[英]how to delete all files with a path pattern
I have a backup location, which uses hardlinks to store existing or changed files. 我有一个备份位置,它使用硬链接来存储现有或已更改的文件。 The location of these backups mimick the linux file system with a date part in it.
这些备份的位置模仿linux文件系统,其中包含日期部分。
For example I have files 例如,我有文件
/backup/servername/2012-06-26T00.43.01/www.website.com/file1.html
/backup/servername/2012-06-26T06.43.01/www.website.com/file1.html
/backup/servername/2012-06-26T06.43.01/www.website.com/file2.html
/backup/servername/2012-06-26T12.43.01/www.website.com/file1.html
/backup/servername/2012-06-26T12.43.01/www.website.com/file2.html
How can I find all files which have www.website.com in them, so I can delete them 如何查找其中包含www.website.com的所有文件,以便删除它们
I have this command combination to delete files I can find with find, but I can't figure out how to find these files. 我有这个命令组合来删除我用find找到的文件,但我无法弄清楚如何找到这些文件。
find . -name 'filename.*' -print0 | xargs -0 rm
You're being a little loose with your terminology, so it's a kind of tough to understand what exactly you want. 你的术语有点松散,所以你很难理解你想要什么。 However, if I understood you correctly, you want to delete all the files within a directory called
www.website.com
: 不过,如果我理解正确的话,你要删除一个名为目录中的所有文件
www.website.com
:
find . -wholename '*/www.website.com/*.html' -delete
if i understood you right you can use smth like this: find /backup/servername/2012-06-26T12.43.01/www.website.com/ -iname '*file*' -print0 | xargs -0 rm
如果我理解你,你可以像这样使用smth:
find /backup/servername/2012-06-26T12.43.01/www.website.com/ -iname '*file*' -print0 | xargs -0 rm
find /backup/servername/2012-06-26T12.43.01/www.website.com/ -iname '*file*' -print0 | xargs -0 rm
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