如何使用MS SQL中的LIKE语句从表中选择包含大写字母的行仅包含西里尔字符的行

Question

I want to select rows where column [Name] contains ONLY Cyrillic characters in UPPERCASE, and comma and hyphen from the table using LIKE :

SELECT  *
FROM    Clients
WHERE   NAME    LIKE '%[А-Я][,-]%' COLLATE Cyrillic_General_CS_AS

Or using explicit pattern:

SELECT *
FROM Clients
WHERE NAME LIKE '%[АБВГДЕЁЖЗИЙКЛМНОПРСТУФХЦЧШЩЪЫЬЭЮЯ][,-]%' COLLATE Cyrillic_General_CS_AS

But these selects rows in which at least one character exists in pattern (but allows any other characters not exists in pattern).

Maybe using ^ (NOT predicate) excluding any other characters like this:

SELECT  *
FROM    Clients
WHERE   NAME    LIKE '%[^A-Z][./=+]%' COLLATE Cyrillic_General_CS_AS

But this requires enumeration a large number of unnecessary characters.

How best to make a selection?

Answer 1

Use a double negative. Search for rows where the column doesn't contain at least one character not in the set you're interested in:

SELECT *
FROM Clients
WHERE NAME NOT LIKE '%[^-АБВГДЕЁЖЗИЙКЛМНОПРСТУФХЦЧШЩЪЫЬЭЮЯ,]%' COLLATE Cyrillic_General_CS_AS

(I'm not quite sure what you were attempting to do by placing the hyphen and comma in a separate grouping, but I've moved them into the same group for now, since that seems to make some sense)