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按归属关系中的父项排序active_admin列

[英]order active_admin column by parent item in belongs_to relationship

I have two models: show_request and show . 我有两个模型: show_requestshow A show_Request belongs_to a show and a show has_many show_requests . 一个show_Request属于一个show ,一个show has_many show_requests On the show_request page in active_admin, I want to order show_requests by the show 's created_at value. 在active_admin的show_request页面上,我想通过showcreated_at值对show_requests进行排序。 Here is my code so far: 到目前为止,这是我的代码:

ActiveAdmin.register ShowRequest do

  controller do
    def scoped_collection
      end_of_association_chain.includes(:show)
      #I also tried ShowRequest.includes(:show)
    end
  end

  index do
    column 'Show', sortable: "shows.created_at_asc" do |show_req|
        link_to show_req.show.name, admin_show_path(show_req.show)
    end
  end

end

Here are the server logs: 这是服务器日志:

Started GET "/admin/show_requests" for 127.0.0.1 at 2015-09-18 09:35:36 -0400
Processing by Admin::ShowRequestsController#index as HTML
  AdminUser Load (0.3ms)  SELECT  "admin_users".* FROM "admin_users"  WHERE "admin_users"."id" = 1  ORDER BY "admin_users"."id" ASC LIMIT 1
   (1.2ms)  SELECT COUNT(*) FROM "show_requests"  WHERE (not_going_to_show = 'f' OR i_want_my_horse_to_compete = 't')
   (0.2ms)  SELECT COUNT(*) FROM "show_requests"
   (0.2ms)  SELECT COUNT(*) FROM "show_requests"  WHERE (not_going_to_show = 't' AND i_want_my_horse_to_compete = 'f')
   (0.3ms)  SELECT COUNT(count_column) FROM (SELECT  1 AS count_column FROM "show_requests"  WHERE (not_going_to_show = 'f' OR i_want_my_horse_to_compete = 't') LIMIT 30 OFFSET 0) subquery_for_count
  CACHE (0.0ms)  SELECT COUNT(count_column) FROM (SELECT  1 AS count_column FROM "show_requests"  WHERE (not_going_to_show = 'f' OR i_want_my_horse_to_compete = 't') LIMIT 30 OFFSET 0) subquery_for_count
  CACHE (0.0ms)  SELECT COUNT(*) FROM "show_requests"  WHERE (not_going_to_show = 'f' OR i_want_my_horse_to_compete = 't')
  CACHE (0.0ms)  SELECT COUNT(count_column) FROM (SELECT  1 AS count_column FROM "show_requests"  WHERE (not_going_to_show = 'f' OR i_want_my_horse_to_compete = 't') LIMIT 30 OFFSET 0) subquery_for_count
  ShowRequest Load (2.0ms)  SELECT  "show_requests".* FROM "show_requests"  WHERE (not_going_to_show = 'f' OR i_want_my_horse_to_compete = 't')  ORDER BY "show_requests"."id" desc LIMIT 30 OFFSET 0
  Show Load (9.7ms)  SELECT "shows".* FROM "shows"  WHERE "shows"."id" IN (2, 1)
  User Load (0.4ms)  SELECT  "users".* FROM "users"  WHERE "users"."id" = $1 LIMIT 1  [["id", 2]]
  User Load (0.2ms)  SELECT  "users".* FROM "users"  WHERE "users"."id" = $1 LIMIT 1  [["id", 1]]
  CACHE (0.0ms)  SELECT  "users".* FROM "users"  WHERE "users"."id" = $1 LIMIT 1  [["id", 1]]
  Show Load (0.2ms)  SELECT "shows".* FROM "shows"
  User Load (0.2ms)  SELECT "users".* FROM "users"

This is not working. 这是行不通的。 It is not affecting the order of the columns at all. 它根本不影响列的顺序。 How do I fix this? 我该如何解决?

Take a look at this part of the log: 看一下日志的这一部分:

ShowRequest Load (2.0ms)  SELECT  "show_requests".* FROM "show_requests"  WHERE (not_going_to_show = 'f' OR i_want_my_horse_to_compete = 't')  ORDER BY "show_requests"."id" desc LIMIT 30 OFFSET 0
Show Load (9.7ms)  SELECT "shows".* FROM "shows"  WHERE "shows"."id" IN (2, 1)

You can see that the ShowRequest s and Show s are loaded in separate queries. 您可以看到ShowRequestShow分别在不同的查询中加载。 sortable is not going to work here, because you can't order one table by a field of another without a join. sortable在这里不起作用,因为没有连接就无法按另一个表的字段对一个表进行排序。 The fix should be to tell ActiveRecord that you need to reference the shows table in your query: 解决方法应该是告诉ActiveRecord您需要在查询中引用shows表:

controller do
  def scoped_collection
    super.includes(:show).references(:shows)
  end
end

index do
  column :show, sortable: 'shows.created_at'
end

references only works with includes , and forces Rails to perform a join when eager loading. references仅与includes ,并在急切加载时强制Rails执行联接。

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