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[英]rails4-autocomplete gem with active_admin and belongs_to relation
[英]order active_admin column by parent item in belongs_to relationship
我有兩個模型: show_request
和show
。 一個show_Request
屬於一個show
,一個show
has_many show_requests
。 在active_admin的show_request
頁面上,我想通過show
的created_at
值對show_requests
進行排序。 到目前為止,這是我的代碼:
ActiveAdmin.register ShowRequest do
controller do
def scoped_collection
end_of_association_chain.includes(:show)
#I also tried ShowRequest.includes(:show)
end
end
index do
column 'Show', sortable: "shows.created_at_asc" do |show_req|
link_to show_req.show.name, admin_show_path(show_req.show)
end
end
end
這是服務器日志:
Started GET "/admin/show_requests" for 127.0.0.1 at 2015-09-18 09:35:36 -0400
Processing by Admin::ShowRequestsController#index as HTML
AdminUser Load (0.3ms) SELECT "admin_users".* FROM "admin_users" WHERE "admin_users"."id" = 1 ORDER BY "admin_users"."id" ASC LIMIT 1
(1.2ms) SELECT COUNT(*) FROM "show_requests" WHERE (not_going_to_show = 'f' OR i_want_my_horse_to_compete = 't')
(0.2ms) SELECT COUNT(*) FROM "show_requests"
(0.2ms) SELECT COUNT(*) FROM "show_requests" WHERE (not_going_to_show = 't' AND i_want_my_horse_to_compete = 'f')
(0.3ms) SELECT COUNT(count_column) FROM (SELECT 1 AS count_column FROM "show_requests" WHERE (not_going_to_show = 'f' OR i_want_my_horse_to_compete = 't') LIMIT 30 OFFSET 0) subquery_for_count
CACHE (0.0ms) SELECT COUNT(count_column) FROM (SELECT 1 AS count_column FROM "show_requests" WHERE (not_going_to_show = 'f' OR i_want_my_horse_to_compete = 't') LIMIT 30 OFFSET 0) subquery_for_count
CACHE (0.0ms) SELECT COUNT(*) FROM "show_requests" WHERE (not_going_to_show = 'f' OR i_want_my_horse_to_compete = 't')
CACHE (0.0ms) SELECT COUNT(count_column) FROM (SELECT 1 AS count_column FROM "show_requests" WHERE (not_going_to_show = 'f' OR i_want_my_horse_to_compete = 't') LIMIT 30 OFFSET 0) subquery_for_count
ShowRequest Load (2.0ms) SELECT "show_requests".* FROM "show_requests" WHERE (not_going_to_show = 'f' OR i_want_my_horse_to_compete = 't') ORDER BY "show_requests"."id" desc LIMIT 30 OFFSET 0
Show Load (9.7ms) SELECT "shows".* FROM "shows" WHERE "shows"."id" IN (2, 1)
User Load (0.4ms) SELECT "users".* FROM "users" WHERE "users"."id" = $1 LIMIT 1 [["id", 2]]
User Load (0.2ms) SELECT "users".* FROM "users" WHERE "users"."id" = $1 LIMIT 1 [["id", 1]]
CACHE (0.0ms) SELECT "users".* FROM "users" WHERE "users"."id" = $1 LIMIT 1 [["id", 1]]
Show Load (0.2ms) SELECT "shows".* FROM "shows"
User Load (0.2ms) SELECT "users".* FROM "users"
這是行不通的。 它根本不影響列的順序。 我該如何解決?
看一下日志的這一部分:
ShowRequest Load (2.0ms) SELECT "show_requests".* FROM "show_requests" WHERE (not_going_to_show = 'f' OR i_want_my_horse_to_compete = 't') ORDER BY "show_requests"."id" desc LIMIT 30 OFFSET 0
Show Load (9.7ms) SELECT "shows".* FROM "shows" WHERE "shows"."id" IN (2, 1)
您可以看到ShowRequest
和Show
分別在不同的查詢中加載。 sortable
在這里不起作用,因為沒有連接就無法按另一個表的字段對一個表進行排序。 解決方法應該是告訴ActiveRecord您需要在查詢中引用shows
表:
controller do
def scoped_collection
super.includes(:show).references(:shows)
end
end
index do
column :show, sortable: 'shows.created_at'
end
references
僅與includes
,並在急切加載時強制Rails執行聯接。
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