[英]2D Array with user input and random numbers
I am trying to generate a program that ask the user a number "n" and displays a 2 xn array. 我正在尝试生成一个要求用户输入数字“ n”并显示2 xn数组的程序。 Eg: 例如:
1 2 3 4 5 (User input) 1 2 3 4 5(用户输入)
5 8 2 1 5 (Random numbers) 5 8 2 1 5(随机数字)
I can't see to make my code to work. 我看不到使我的代码正常工作。 Here is my code: 这是我的代码:
import java.util.Scanner;
public class Main {
/**
* @param args the command line arguments
*/
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter number of exits: ");
int n = input.nextInt();
int [][] A = new int[2][n];
for (int i =0; i <= A[n].length; i++){
A[i][n]= (int)(Math.random()*10);
}
System.out.println(A[2][n]);
System.out.print("Distance between exit i and exit j is: " + distance());
}
public static int distance(){
Scanner input = new Scanner(System.in);
System.out.print("Please enter exit i: ");
int i = input.nextInt();
System.out.print("Please enter exit j: ");
int j = input.nextInt();
return i + j;
}
}
I am getting this error 我收到此错误
"Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 5" “线程“主”中的异常java.lang.ArrayIndexOutOfBoundsException:5”
How can I fix it? 我该如何解决? And I think my Math.random is wrong. 而且我认为我的Math.random是错误的。 Can you guys help me with some advises or where am I doing things wrong? 你们能为我提供一些建议还是我在哪里做错了事? Thanks. 谢谢。
All your errors lie within and after your for-loop: 您的所有错误都在for循环之内和之后:
for (int i =0; i <= A[n].length; i++){
A[i][n]= (int)(Math.random()*10);
}
If n = 5, A[5].length does not exist, because the first dimensions of your array only exist between 0 and 1. A[2] reserves space for 2 int primitives, the first is at index 0 and the last is at index 1. Even if that is changed, the i variable your for loop declares is incremented beyond 1 and so the JVM will throw a ArrayIndexOutOfBoundsException. 如果n = 5,则不存在A [5] .length,因为数组的第一个维仅存在于0和1之间。A[2]保留2个int图元的空间,第一个在索引0处,最后一个在索引处在索引1处。即使已更改,for循环声明的i变量也将增加到1以上,因此JVM将抛出ArrayIndexOutOfBoundsException。
When declaring an array with the dimensions [2][n], (given n is an Integer, which will be provided by the user via the scanner) you cannot access arrayReference [2][x] 在声明尺寸为[2] [n]的数组时(假设n为整数,这将由用户通过扫描仪提供),您将无法访问arrayReference [2] [x]
Arrays are based on a 0 index structure ... 数组基于0索引结构 ...
Consider the following: 考虑以下:
int [][] A = new int[2][2]; int [] [] A =新的int [2] [2];
You can only access A[0][0], A[0][1], A[1][0] & A[1][1]. 您只能访问A [0] [0],A [0] [1],A [1] [0]和A [1] [1]。
you CANNOT access A[2][0], A[2][1] or A[2][2]. 你不能访问A [2] [0],A [2] [1]或A [2] [2]。
Here's what you need to do: 这是您需要做的:
//A.length will give you the length of the first dimension (2)
for(int i=0; i<A.length; i++){
for(int j=0; j<n; j++){
A[i][j] = (int) (Math.random()*10);
}
}
}
System.out.println(A[1][n-1]);
System.out.print("Distance between exit i and exit j is: " + distance());
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