Java.split("|") 不工作

Question

I just ran into the problem that the split method for strings wouldn't work with character "|"as an argument. It somehow separates each character in the string.

Code:

String[] res = "12345|6".split("|");
Log.d("split", Arrays.toString(res));

Output:

split﹕ [, 1, 2, 3, 4, 5, |, 6]

Answer 1

Use escape character before |like below:

String[] res = "12345|6".split("\\|");

Similar "escape character logic" is required, when you are dealing/splitting with any of the below special characters (used by Regular Expression):

• OR sign (|)
• question mark (?)
• asterisk (*)
• plus sign (+)
• backslash (\\)
• period (.)
• caret (^)
• square brackets ([ and ])
• dollar sign ($)
• ampersand (&)

Answer 2

| is a regular expression key character and split() works with regualar expressions. Escape it like this: \\\\|

Answer 3

You can try to escape it like this:

String[] res = "12345|6".split("\\|");

Pipe has special meaning in regular expression and it allows regular expression components to be logically ORed. So all you need to escape it using the \\\\

Answer 4

If you have split using "||"then you use :

      yourstring.split(Pattern.quote("||"))

Answer 5

You can try this, simple and easy.

String[] res = "12345|6".split("[|]");

Answer 6

public static void main(String[] args) {
    String data = "12345|6|7|990";
    String[] arr = data.split("\\|");
    for(int i = 0 ; i< arr.length; i++){
      System.out.println(arr[i]);
    }
  }

O/p : 12345
6
7
990

Answer 7

However, I already found a quick fix for this: use ASCII code as argument ->

String[] res = "12345|6".split("\\x7C");
Log.d("split", Arrays.toString(res));

Output:

split﹕ [12345, 6]

Just wanted to share this here so others with same issue can also use this fix. :)