如何在C中打印字符串的二维数组（带空格）？

Question

I am trying to print out a two dimensional array of strings using the array shown below and associate each phrase with a number from 0 to 3. When I try to print out each phrase the words get matched together and print out incorrectly.

char PhraseList[4][10]= {" Work Hard","Play Hard ","Enjoy","Live"};

How can I print out each phrase on a separate line so that " Work Hard" prints out on one line then "Play Hard " on another line and then "Enjoy" on another etc. Also how can I associate each phrase with a number? Any help\\suggestions will be greatly appreciated!

Here is my code:

#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <ctype.h>
#include <string.h>
#include <math.h>



int main()
{
char PhraseList[4][10]= {" Work Hard","Play Hard ","Enjoy","Live"};

int i;

for(i=0; i<4; i++)
{
    printf("%s \n", PhraseList[i]);
}


printf("\n\n");
system("PAUSE");
return 0;
}

---

Output:

 Work HardPlay Hard Enjoy
Play Hard Enjoy
Enjoy
Live


Press any key to continue . . .

---

Answer 1

Your printf calls are fine. The real problem is that you are overflowing the buffer. Each string has been given 10 bytes maximum storage. But in C strings are by definition NUL terminated. So you need an extra byte to store that NUL .

Better not to specify a fixed size at all. Can just do this:

const char *PhraseList[]= {" Work Hard","Play Hard ","Enjoy","Live"};

Answer 2

As pointed out in the comment, the leading and trailing space in " Work Hard" and "Play Hard " respectively is the reason for issue.

The size of each of these is 11 characters (not 10).

" '[space]' 'W' 'o' 'r' 'k' '[space]' 'h' 'a' 'r' 'd' '\0'"

which results in 11 characters.

Hence increase the size of PhraseList and declare it as

char PhraseList[4][11]= {" Work Hard","Play Hard ","Enjoy","Live"};

or

const char *PhraseList[]= {" Work Hard","Play Hard ","Enjoy","Live"};

Answer 3

You allocate too little memory for your strings.

Lets look " Work Hard". In memory this string is stored as ' ', 'W', 'o', 'r', 'k', ' ', 'H', 'a', 'r', 'd', '\\0', that is in it requires 11 bytes.

But you allocate 10 bytes only. Change type to PhraseList[4][11] .

Answer 4

you could either get rid of your leading and trailing whitspaces or make you array bigger. If you want to output Number associated with the array just add the i variable to your output.

int main()
{
char PhraseList[4][10] = { "Work Hard","Play Hard","Enjoy","Live" };

int i;

for (i = 0; i<4; i++)
{
    printf("%d %s \n", i, PhraseList[i]);
}

printf("\n\n");
system("PAUSE");
return 0;
}

Answer 5

• First Solution:

• Just remove space from your array's first and second string.Because it is exceded the araay string length.

• Second Solution:

• Just increase your array's string size,

• Instead of this,

   char PhraseList[4][10] = { " Work Hard","Play Hard ","Enjoy","Live" }; 

• Declare it like this,

   char PhraseList[4][15] = { " Work Hard","Play Hard ","Enjoy","Live" };