[英]Check if a digit is present in a list of numbers
How can I see if an index contains certain numbers? 如何查看索引是否包含某些数字?
numbers = [2349523234, 12345123, 12346671, 13246457, 134123431]
for number in numbers:
if (4 in number):
print(number + "True")
else:
print("False")
You would have to do string comparisons for this 你必须为此进行字符串比较
for number in numbers:
if '4' in str(number):
print('{} True'.format(number))
else:
print("False")
It isn't really meaningful to ask if the number 4
is "in" another number (unless you have some particular definition of "in" in mind) 询问数字
4
是否在“另一个数字”中是没有意义的(除非你对“in”有一些特定的定义)
You can convert the number to string and if you want to get the first number that has 4
in it you can use a generator expression within next
: 您可以将数字转换为字符串,如果您想获得其中包含
4
的第一个数字,您可以next
使用生成器表达式:
>>> next(i for i in numbers if '4' in str(i))
2349523234
Or you can use a list comprehension if you want to preserve the number that satisfy the condition: 或者,如果要保留满足条件的数字,则可以使用列表推导:
expected_numbers=[i for i in numbers if '4' in str(i)]
But from a mathematical point of view you can generate all the digits using following function: 但是从数学的角度来看,您可以使用以下函数生成所有数字:
In [1]: def decomp(num):
...: while num:
...: yield num % 10
...: num = num // 10
Then you can do the following: 然后,您可以执行以下操作:
In [3]: numbers = [2349523234, 12345123, 12346671, 13246457, 134123431]
In [4]: [n for n in numbers if any(4==i for i in decomp(n))]
Out[4]: [2349523234, 12345123, 12346671, 13246457, 134123431]
Klist = []
count = 0
while count < 1000:
count += 1
Klist.append(count)
for k in Klist:
if '6' in str(k):
print(k)
You create the list and then iterate through the numbers but as a string. 您创建列表然后迭代数字,但作为字符串。
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