如何将列表拆分为 2 位数字

Question

I have this:
a = ['a','b','c','d','e','f']

And I want to make it into this:
a = ['ab','cd','ef']

What is the simplest way to about it?

Answer 1

def pair_up(a):
    return [a[i]+a[i+1] for i in range(0,len(a),2)]
print(pair_up(a))