python 2.7-如何在分隔符为数字和'\\\\ n'时将字符串转换为列表

Question

for example i have the string :

"hello0there\\nhow3are6you1today?"

what i want to get is :

["hello", "there", "how", "are", "you", "today?"]

the digits represent spaces, and the \\\\n is a new line. i've tried split() to do it but it can only get 2 arguements and not more, so it's not optinal.

i also found this :

filter(None, re.split("['1234567890']+", string_to_split))

which works fine for the digits, yet not for the '\\\\n' . is there any way to split the string by the digits and the '\\\\n' in one action?

i cant figure out a way to split it in two separated functions because once I've created a list i cannot split it again.

if anyone knows of a way to do so, please help me. thanks

Answer 1

You need to add \\s and \\\\n to your regex :

>>> s="hello0there\\nhow3are6you1today?"
>>> re.split(r'[\d\s\\n]*',s)
['hello', 'there', 'how', 'are', 'you', 'today?']

For getting ride of splitting with n 's in your strings you can use a positive look behind and and an logical or :

>>> re.split(r'[\d\s\\]|(?<=\\)n',s)

But since it might produce an empty string you can use a list comprehension to get ride of that.

>>> [i for i in re.split(r'[\d\s\\]|(?<=\\)n',s) if i]