使用python从文件夹读取文件

Question

I am trying to read all files within a directory.

for root, dirs,files in os.walk(path):
        for j in files:
            print(str(j))

This is my code where path is the path of the directory to be read.But it does not print the files in the order of their names. In my case, I have files from 0.txt , 1.txt ,.... to 3590.txt . I want it to print the files in the same order. But rather it starts from 579.txt . How can I fix this? I want to do some computation on the files in the same order and so just storing the names in a list and sorting it wont help.

Answer 1

what about sorting them with a lambda to use the int in the filename:

for root, dirs,files in os.walk(path):
    for j in sorted(files, key=lambda key: int(key.replace(".txt", ""))):
        print(str(j))

Answer 2

As file name structure is like $Number$.txt , so we can sort by Number.

Demo :

>>> l = ["0.txt", "1.txt", "33.txt", "2.txt", "10.txt", "11.txt"]
>>> sorted([(int(i.replace(".txt", "")), i) for i in l ])
[(0, '0.txt'), (1, '1.txt'), (2, '2.txt'), (10, '10.txt'), (11, '11.txt'), (33, '33.txt')]
>>> [i[1] for i in sorted([(int(i.replace(".txt", "")), i) for i in l ])]
['0.txt', '1.txt', '2.txt', '10.txt', '11.txt', '33.txt']