[英]How to check spaces in a string C?
I am trying to have my program take a name as input from the user and then print out the initials of that name.我试图让我的程序从用户那里输入一个名称,然后打印出该名称的首字母。 ie tommy brown --> tb
即汤米布朗 --> tb
What I have so far is this:到目前为止,我所拥有的是:
int main (void)
{
char scroll[100] = {"kang cheng junga"};
printf ("%c\n", *(scroll+2));
for (int i=0; i<100; i++)
{
if (*(scroll+i)=" ")
{
printf (*(scroll+i+1));
}
}
I keep getting this error:我不断收到此错误:
error: incompatible pointer to integer conversion assigning to 'char' from 'char [2]'
错误:从“char [2]”分配给“char”的整数转换指针不兼容
[-Werror,-Wint-conversion] if (*(scroll+i)=" ")
[-Werror,-Wint-conversion] if (*(scroll+i)="")
error: using the result of an assignment as a condition without parentheses
错误:使用赋值结果作为不带括号的条件
[-Werror,-Wparentheses] if (*(scroll+i)=" ")
[-Werror,-W括号] if (*(scroll+i)="")
Can anyone tell me how I've screwed this up?谁能告诉我我是怎么搞砸的? I am having a hard time understanding how * and & function in a C. I am a beginner so I don't really know what I'm doing.
我很难理解 * 和 & 在 C 中的功能。我是一个初学者,所以我真的不知道我在做什么。
In addition to strtok
, this is one time you can also make use of strpbrk
to easily find each space
:除了
strtok
,这是您还可以利用strpbrk
轻松找到每个space
:
#include <stdio.h>
#include <string.h>
int main (void) {
char scroll[100] = "kang cheng junga";
char *p = scroll;
printf ("\n full name: %s\n", scroll);
printf (" initials : %c", *p);
while ((p = strpbrk (p, " ")))
printf ("%c", *++p);
printf ("\n\n");
return 0;
}
Output输出
$ ./bin/initials
full name: kang cheng junga
initials : kcj
You can also eliminate the dependence on string.h
with an alternative version that uses pointers alone:您还可以使用单独使用指针的替代版本来消除对
string.h
的依赖:
#include <stdio.h>
int main (void) {
char scroll[100] = "kang cheng junga";
char *p = scroll;
printf ("\n full name: %s\n", scroll);
printf (" initials : %c", *p);
while (*p++)
if (*p == ' ' && *++p)
printf ("%c", *p);
printf ("\n\n");
return 0;
}
The Error you are getting is because of the assignment operator (=) .你得到的错误是因为赋值运算符 (=) 。
if (*(scroll+i)=" ")// assigning a value(blank)
{
printf (*(scroll+i+1));
}
if (*(scroll+i) == ' ')//Comparing it with a value (blank)
{
printf (*(scroll+i+1));
}
In C, =
is assignment operator, and ==
is equality operator.在 C 中,
=
是赋值运算符,而==
是相等运算符。 You need to use the later one.您需要使用后者。
That said, there is a nice library function, named strtok()
which can make your life easier.也就是说,有一个很好的库函数,名为
strtok()
,它可以让您的生活更轻松。 Just pass the string and a delimiter, (here, the space只需传递字符串和分隔符,(这里是空格
) and it will return the token to you, for which you can print the first character to get the initials.
),它会将令牌返回给您,您可以打印第一个字符以获取首字母。
along with strtok or strchr here is a simple way to implement , some boundary conditions are missing like name ending with single letter etc与 strtok 或 strchr 一起,这里是一种简单的实现方法,缺少一些边界条件,例如名称以单个字母结尾等
#include <stdio.h>
int main (void)
{
int i = 0;
char scroll[100] = {"kang cheng junga"};
char *p = scroll; // point to base
printf("%c", *p ); // first letter is almost always certain
while( *p != '\0' ) { // till end of String
if ( *(p-1) == ' ' && *(p+1) != '\0') { // If previous is space and next letter exists
printf("%c", *p ); // take it save it or print it
}
p ++ ; //proceed
}
return 0;
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.