按顺序打印3位数字的数字

Question

I am currently trying to create a program that requests a 3 digit number from the user and prints out the individual digits of the number in order, eg:

"Input 3 digits: 123"
1
2
3

I am not allowed to use any form of strings, just mathematical operations.

Also, I have gotten formulas for the second and third digit but cannot get the first for the life of me, and when I run the program the first and the second digit return with a decimal number which I am not sure how to avoid.

My code:

n = eval(input('Enter a 3-digit number: '))
c = n % 10
b = n - c
b = b / 10
b = b % 10
a = n / b
a = a % 10
print(a)
print(b)
print(c)

Answer 1

There's a much easier way to do this that doesn't require any math. In Python, strings are iterable and input() returns a string. So you can just do this:

n = input('enter a number: ')
for x in n:
    print(x)

Answer 2

Divide your number by 100, inside of a call to int :

Input 3 digits: 435

firstDigit = int(n / 100)

firstDigit will be 4

Answer 3

You get the input as a string so, using your example, you would get '123'. If you're not obligated to use the formulas, you could get each digit as follows:

user_input = input('Enter a 3-digit number: ')
first_digit, second_digit, third_digit = [int(digit) for digit in user_input]
print first_digit
print second_digit
print third_digit 

Answer 4

THe problem is where you divide n by b -- no reason to divide the original number by its second digit. You probably wanted to divide by 10 again.

It's easier if you remember that when you divide integers , you get an integer -- so, for example: 329 / 10 gives 32 That save you from having to subtract at all (also, clearer variable names make it much more readable):

dig3 = n % 10
n = n/10
dig2 = n % 10
dig1 = n/10

Answer 5

I think you are looking for this:

n = eval(input('Enter a 3-digit number: '))
c = n % 10
b = int(n / 10)
b = b % 10
a = int(n / 100)
a = a % 10
print(a)
print(b)
print(c)