如何使区分大小写的代码按名称上传文件

Question

So i have more than one image to upload, each one being a new line in my mysql table:

I use this code for file input with name="profile"

if (isset($_FILES['profile']) === true) {
if (empty($_FILES['profile']['name']) === true) {
    echo 'Please choose a file!';
}else {
    $allowed= array('jpg', 'jpeg', 'png')       
    $file_name = $_FILES['profile']['name'];
    $file_exts = explode('.', $file_name);
    $file_extn = strtolower(end($file_exts));
    $file_temp = $_FILES['profile']['tmp_name'];
    if (in_array($file_extn, $allowed) === true) {
        change_image($session_user_id, 1, $file_temp, $file_extn);
        header('Location: galery.php');
        exit();
    }else {
        echo 'Incorrect file type . allowed files are : ';
        echo implode(", ", $allowed);

(change_image) function makes this MySql query

$sql = "UPDATE `art_$id` SET `path` = \"" . $file_path . "\" WHERE `row` = " . (int)$row;

But i want to repeat this code for profil1, profil2... and change accordingly the row (example : profil4 would change row 4 ), without having to repeat this code for each file='name'.

How would i go about that?

Answer 1

Irrespective of your form have "how many fields as of file and what they are named??" . Following code will upload them one by one ..Check it

 $rowid=1;
    foreach($_FILES as $key=>$image_uploaded)
    {
    if (isset($image_uploaded[$key]) === true) {
    if (empty($image_uploaded[$key]['name']) === true) {
        echo 'Please choose a file!';
    }else {
        $allowed= array('jpg', 'jpeg', 'png')       
        $file_name = $image_uploaded[$key]['name'];
        $file_exts = explode('.', $file_name);
        $file_extn = strtolower(end($file_exts));
        $file_temp = $image_uploaded[$key]['tmp_name'];
        if (in_array($file_extn, $allowed) === true) {
            change_image($session_user_id, $rowid++, $file_temp, $file_extn);
            //change as you need
            header('Location: galery.php');
            exit();
        }else {
            echo 'Incorrect file type . allowed files are : ';
            echo implode(", ", $allowed);
    }

Answer 2

Thanks for your answer, as i have a specific submit button for each form and don't wont to validate all forms at once i used this code :

for ($row = 1; $row <= 9; $row++) {
if (isset($_FILES["profile" . $row]) === true) {
if (empty($_FILES["profile" . $row]['name']) === true) {
    echo 'Please choose a file!';
}else {
    $allowed= array('jpg', 'jpeg', 'png');

    $file_name = $_FILES["profile" . $row]['name'];
    $file_exts = explode('.', $file_name);
    $file_extn = strtolower(end($file_exts));
    $file_temp = $_FILES["profile" . $row]['tmp_name'];

    if (in_array($file_extn, $allowed) === true) {
        change_image($session_user_id, $row, $file_temp, $file_extn);
        //header('Location: galery.php');
        //exit();
    }else {
        echo 'Incorrect file type . allowed files are : ';
        echo implode(", ", $allowed);

          }



}

}
}

And for file input i use name="profile1",name="profile2",....,name="profile9"(for this case).

Answer 3

Here is the the code which will add 1,2,3 at end of the image file name Bellow function will check the file exist in dir or not and return new file name now you can use the function before change_image function call and get new file name and pass new name in change_image for save.

function getFileName($fileName, $file_extn){
    $fileNameWithoutExt = pathinfo($fileName, PATHINFO_FILENAME);
    $i = 1;
    while(!file_exists('image/art/' . $fileName)){
          $fileName = $fileNameWithoutExt . $i . "." . $file_extn;
          $i++;
    }
    return  $fileName;
}