[英]why this C++ program gives incorrect output?
Consider following program:考虑以下程序:
#include <iostream>
int main()
{
std::cout<<std::ios::showbase<<123<<", "<<std::hex<<123<<", "<<std::oct<<123<<'\n';
}
Expected Output: 123, 0x7b, 0173预期输出:123、0x7b、0173
Acquired Output: 512123, 7b, 173 (see live demo here: http://ideone.com/Khzj5j )获得的输出:512123、7b、173(在此处查看现场演示: http ://ideone.com/Khzj5j)
But If I modify the above program slightly as following:但是如果我稍微修改上面的程序如下:
#include <iostream>
using namespace std;
int main()
{
cout<<showbase<<123<<", "<<hex<<123<<", "<<oct<<123<<'\n';
}
Now I got desired output.现在我得到了想要的输出。 (see live demo here http://ideone.com/gcuHbm ). (在此处查看现场演示http://ideone.com/gcuHbm )。
Why first program gave incorrect output but 2nd program doesn't?为什么第一个程序给出了错误的输出,而第二个程序却没有? What's going wrong in first program?第一个程序出了什么问题?
std::ios::showbase
is a format flag. std::ios::showbase
是格式标志。 std::showbase
is a function that takes a std::ios_base
and calls ios_base::setf(std::ios::showbase)
on it to set the showbase
flag. std::showbase
是一个函数,它采用std::ios_base
并在其上调用ios_base::setf(std::ios::showbase)
以设置showbase
标志。
You use the prior in your first example and the latter in your second example.您在第一个示例中使用先验,在第二个示例中使用后者。
#include <iostream>
int main()
{
std::cout<<std::ios::showbase<<123<<", "<<std::hex<<123<<", "<<std::oct<<123<<'\n';
}
This uses std::ios::showbase
( http://www.cplusplus.com/reference/ios/ios_base/fmtflags/ )这使用std::ios::showbase
( http://www.cplusplus.com/reference/ios/ios_base/fmtflags/ )
While your other program而你的其他程序
#include <iostream>
using namespace std;
int main()
{
cout<<showbase<<123<<", "<<hex<<123<<", "<<oct<<123<<'\n';
}
Uses std::showbase
( http://en.cppreference.com/w/cpp/io/manip/showbase ) which is why you're getting different results.使用std::showbase
( http://en.cppreference.com/w/cpp/io/manip/showbase ) 这就是你得到不同结果的原因。
Changing the first program to use std::showbase
gives you your expected output:更改第一个程序以使用std::showbase
为您提供预期的输出:
#include <iostream>
int main()
{
std::cout<<std::showbase<<123<<", "<<std::hex<<123<<", "<<std::oct<<123<<'\n';
}
std::ios::showbase
is a format flag that has some implementation defined value. std::ios::showbase
是一个格式标志,具有一些实现定义的值。 When you call std::cout << std::ios::showbase
you are displaying that value and not setting the stream format flag.当您调用std::cout << std::ios::showbase
您正在显示该值而不是设置流格式标志。
In you second example you are using std::showbase
which sets the format flag of the stream.在第二个示例中,您使用std::showbase
设置流的格式标志。
In std::ios_base
, showbase
is a fmtflag
that has an implementation-defined value.在std::ios_base
, showbase
是具有实现定义值的fmtflag
。 In this case, it appears to be 512
.在这种情况下,它似乎是512
。 On the other hand, there is a stream manipulator (aka, a function) also called showbase
, which calls setf(std::ios_base::showbase)
.另一方面,还有一个流操纵器(又名函数)也称为showbase
,它调用setf(std::ios_base::showbase)
。 This is defined as a free function in namespace std
whereas the fmtflag
is a member of std::ios_base
.这被定义为namespace std
的自由函数,而fmtflag
是std::ios_base
的成员。
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