Python 3 - 从平方值可被 8 整除的列表中打印数字

Question

I'm currently working on a question to determine if a square value in a list is evenly divisible by 8, and then print it out from the list if this is the case. So for example I can have this list:

 list1 = [2, 4, 6, 8, 10, 12]

• 4 squared = 16, which is divisible evenly by 8.

• 8 square = 64, which is divisible by 8, etc.

So, the program has to print the square values that are divisible by 8. I have realised, I have to use the print() function as well as "for" and "in" most likely since its a loop type question.

As a reference, here is the original question:

Print each number in a list whose square is evenly divisible by 8.

For example, if list is

[2, 3, 4, 5, 6, 7, 8, 9]

, then the number 4 is one number that should be printed because 4 squared is 16 and 16 is evenly divisible by 8. Test your code module with two test lists.

Answer 1

Observe that if the square of x is divisible by 8, then x is divisible by 4 , so:

list1 = [2, 4, 6, 8, 10, 12]
print [x for x in list1 if x & 3 == 0]

Answer 2

num_list = [2, 3, 4, 5, 6, 7, 8, 9]

First you iterate over the list. Use the for loop for it. Put your if condition in there if (x * x) % 8 == 0 then print the number :

for num in num_list:
    if (num * num) % 8 == 0:
        print(num)

The key idea is finding the square, for it you use num * num .

To check if a number x is divisible by 8 you use x % 8 == 0