Python-打印不带方括号的函数中的数字列表

Question

I'm generating a list of random digits, but I'm struggling to figure out how to output the digits in a single row without the square brackets?

import random 
def generateAnswer(answerList):

    listofDigits = []
    while len(listofDigits) < 5:
        digit = random.randint(1, 9)
        if digit not in listofDigits:
            listofDigits.append(digit)
    return listofDigits

def main():
    listofDigits = []
    print(generateAnswer(listofDigits))

main()

Answer 1

print(", ".join([str(i) for i in generateAnswer(listofDigits)]))

Answer 2

您可以解压缩列表并使用sep参数：

print(*generateAnswer(listofDigits), sep=' ')

Answer 3

Try this:

listofDigits = []
print(str(generateAnswer(listofDigits))[1:-1])

Also, if generateAnswer initialize and return the list, then you don't need to pass in an empty list. Another thing is that if you want to generate a non-repeating random list, you can use random.sample and range .

I think this is better:

import random 
def generateAnswer():
    return random.sample(range(1, 10), 5)

def main():
    print(str(generateAnswer())[1:-1])

main()

Hope it helps!

Answer 4

The reason you're getting the brackets is because the list class, by default, prints the brackets. To remove the brackets, either use a loop or string.join :

>>> print(' '.join(map(str, listofDigits)))
9 2 1 8 6
>>> for i in listofDigits:
    print(i, end=' ')


9 2 1 8 6 

Note that the last method adds a space at the end.

Note that in the first method, the arguments need to be cast to strings because you can only join strings, not ints.