[英]Converting a double to float
class calc_Payroll
private float hours;
private float rate;
private int hrsStr;
float gross;
calc_Payroll(float a, float b, float c, float d)
{
gross = hours + (hrsStr * 1.33) * rate; //error here
}
I'm confused as to where I have converted anything to a double? 我对将任何内容转换为双精度的地方感到困惑? but the error I am getting is
但是我得到的错误是
cannot covert double to float 无法掩盖双浮
1.33
is a double
literal, and it causes the entire hours + (hrsStr * 1.33) * rate
expression to return a double
value, which can't be assigned to a float
variable without an explicit cast. 1.33
是一个double
hours + (hrsStr * 1.33) * rate
字面量,它使整个hours + (hrsStr * 1.33) * rate
表达式返回一个double
float
值,如果没有显式hours + (hrsStr * 1.33) * rate
,则不能将其分配给float
变量。
Change it to 1.33f
for a float
literal. 将其更改为
1.33f
以获取float
文字。
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