是否有可能创建一个接受任意数量参数的方法？

Question

I was looking at another post here which was describing what seems to be my problem : How to make a method which accepts any number of arguments of any type in Java?

However , when I attempted to do this method, when I compiled the program it gave me the error "int cannot be converted to java.util.Objects"

What am I doing wrong?

Code:

public static void clearArray (Objects... args)
{
    System.out.println("Error, non character value");
}

How I called the function:

import java.util.Objects;
// Stuff...
clearArray(1);
// Other stuff...

Thank you for checking out my problem!

Answer 1

Look at the signature

public static void clearArray (Objects... args)

That method receivng Objects type and you are passing integer to it. Perhaps changing that to

public static void clearArray (Object... args)

Helps.

Answer 2

You want java.lang.Object , not java.util.Objects .

java.util.Objects is a class with utility methods, not a class you can actually extend and instantiate.

java.lang.Object on the other hand is the superclass of all objects in Java.

And even in a multi-param (varargs) method, the signature needs to be Object ... , not Objects ... .