[英]method that takes no arguments and returns double
I need to write a public method costMultiplier() that takes no arguments and returns a double.我需要编写一个不带参数并返回双精度值的公共方法 costMultiplier()。 The method should return 1.2 for postcodes beginning “WC1A” or “EC1A”, and 1.0 otherwise.
对于以“WC1A”或“EC1A”开头的邮政编码,该方法应返回 1.2,否则返回 1.0。
This is what I have so far but I have added an argument.这是我到目前为止所拥有的,但我添加了一个论点。 I am not sure how to answer the question without the argument and how would I test ir accurately.
我不知道如何在没有参数的情况下回答问题,以及如何准确地测试 ir。 Many thanks
非常感谢
public double costMultiplier(final String postCode) {
double multiplier = 1.0d; `
String pc = postCode.trim().toUpperCase();
if (pc.startsWith("WC1A") || pc.startsWith("EC1A")) {
multiplier = 1.2;
}
return multiplier;
}
or I did this but need to include a String???或者我做了这个但需要包含一个字符串???
`public static double costMultiplier(){
if(postCode.contains("WC")
return 1.2;
}
else if(postCode.contains("EC") { return 1.0;}
}
else if(postCode.contains("EC") { return 1.0;}
Perhaps you can create a PostCode
class like:也许您可以创建一个
PostCode
类,例如:
public class PostCode {
private final String code;
public PostCode(String code) {
this.code = code.trim().toUpperCase();
}
public double costMultiplier() {
if (code.startsWith("WC1A") || code.startsWith("EC1A")) {
return 1.2;
}
return 1.0
}
}
then you can do:那么你可以这样做:
new PostCode("WC1A").costMultiplier()
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