JS：制作一个更好的函数以返回条件语句

Question

function conditionForLinks(textNum, linkNum){
            if (textNum == undefined || linkNum == undefined){
                    return "${typeof(contentAsset.custom.brandInfoLinkUrl) !== 'undefined' && contentAsset.custom.brandInfoLinkUrl && typeof(contentAsset.custom.brandInfoLinkText) !== 'undefined' && contentAsset.custom.brandInfoLinkText}"
                }else{
                    return "${typeof(contentAsset.custom.brandInfoLinkUrl"+textNum+") !== 'undefined' && contentAsset.custom.brandInfoLinkUrl"+textNum+" && typeof(contentAsset.custom.brandInfoLinkText"+linkNum+") !== 'undefined' && contentAsset.custom.brandInfoLinkText"+textNum+"}"
                }
        };

So I want this function to return the conditional statement. When no arguments are provided it should display the whole statement without any numbers(function arguments).Else put the arguments(numbers) in the statement. My solution does not looks elegant.

Answer 1

function conditionForLinks (textNum, linkNum) {
    if(textNum == undefined || linkNum == undefined) {
        textNum = '';
        linkNum = '';
    }
    return ["${typeof(contentAsset.custom.brandInfoLinkUrl", textNum, ") !== 'undefined' && contentAsset.custom.brandInfoLinkUrl", textNum, " && typeof(contentAsset.custom.brandInfoLinkText", linkNum, ") !== 'undefined' && contentAsset.custom.brandInfoLinkText", textNum, "}"].join('');
}

Answer 2

I don't know exactly what you are trying to accomplish but here is something:

function conditionForLinks(textNum, linkNum){

  textNum = (textNum == null) ? "" : textNum;
  linkNum = (linkNum == null) ? "" : linkNum;

  return "${typeof(contentAsset.custom.brandInfoLinkUrl"+textNum+") !== 'undefined' && contentAsset.custom.brandInfoLinkUrl"+textNum+" && typeof(contentAsset.custom.brandInfoLinkText"+linkNum+") !== 'undefined' && contentAsset.custom.brandInfoLinkText"+textNum+"}";
}