我如何让 xx="$£A" 成为一个 3 个字符的字符串

Question

I am using Python 2.7

If I set a variable to xx = '$£A' I get a 4 byte string. This is because the £ character has a value > 127. In my script, the first line is:

coding=latin_1

then further down I have tried: xx = bytearray(B'$£A').decode('latin_1') if I print str(len(xx)), I get the value 4.

All I need is as byte array to contain three bytes, ascii value for $, 163=ANSI Latin_1 for £ and ascii value for A.

I would appreciate any help. Thanks

Answer 1

It is dangerous to use characters above 128 unescaped in string constants unless:

• you have a line # coding=xxx as first or second line in your script
• your editor uses the declared encoding

The recommended way is to escape them:

xx = b'$\xa3A'

(above would give the correct latin1 string in Python 2 or the correct latin1 encoded bytes in Python 3, whatever the local encoding could be)