[英]How to sort list inside dict in Python?
I am trying to sort list inside of dict alphabetically but not able to do it. 我试图按字母顺序对dict中的列表进行排序但不能这样做。 My list is
我的名单是
{"B" : ["x", "z", "k"], "A" : ["a", "c", "b"]}
What I want to do is, 我想做的是,
{"A" : ["k", "x", "z"], "B" : ["a", "b", "c"]}
my codes are 我的代码是
a = {"B" : ["x", "z", "k"], "A" : ["a", "c", "b"]}
b = dict()
for key, value in a.items():
b[str(key).replace('"','')] = value
ab = OrderedDict(sorted(b.items(), key=lambda t: t[0]))
for x in ab:
ab[x].sort
return HttpResponse(json.dumps(ab), content_type="application/json")
the output I am getting is 我得到的输出是
{ "A" : ["a", "c", "b"], "B" : ["x", "z", "k"]}
can anyone tell me where is my mistake? 谁能告诉我我的错误在哪里? I am printing out in django template json output.
我在django模板json输出中打印出来。
You aren't actually calling the sort
method. 你实际上并没有调用
sort
方法。 Just specifying sort
will return a reference to the sort
method, which isn't even assigned anywhere in your case. 只是指定
sort
将返回对sort
方法的引用,在您的情况下甚至不会在任何地方分配。 In order to actually call it, you should add parenthesis: 为了实际调用它,你应该添加括号:
for x in ab:
ab[x].sort()
# Here ---^
Not sure if you have a typo in your snippets, but here's one way to sort the values of a dictionary, where the values are lists: 不确定你的片段中是否有拼写错误,但这里有一种方法可以对字典的值进行排序,其中值是列表:
>>> d1 = {"B" : ["x", "z", "k"], "A" : ["a", "c", "b"]}
>>> d2 = {x:sorted(d1[x]) for x in d1.keys()}
>>> d2
{'A': ['a', 'b', 'c'], 'B': ['k', 'x', 'z']}
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