如何通过对象字符串值之一对对象数组进行数字排序？

Question

I have an array of objects similar to this :

 var this array = [
    { 
    "id" : "A20",
    "age" : "16"
    },
    {
    "id" : "A2",
    "age" : "12"
    },
    { 
    "id" : "B16",
    "age" : "45"
    }]

I need to sort this array by their ID, So it would end up like :

this array = [
        { 
        "id" : "A2",
        "age" : "12"
        },
        {
        "id" : "A20",
        "age" : "16"
        },
        { 
        "id" : "B16",
        "age" : "45"
        }]

I have this method of sorting :

nodes.sort(function(a,b){
    // console.log(a.Pos)
    // console.log(a.pinNum)
    var alc = a.id, blc = b.id;
    console.log(alc)
    return alc > blc ? 1 : alc < blc ? -1 : 0;
    });

But this only works alphabetically. I have also found this but it gives back just the strings I pass to the function not the array of objects :

function sortArray(arr) {
        var tempArr = [],
        n;
        console.log(arr)
        for (var i in arr) {

            var thisString = arr[i].id;

            // tempArr[i] = arr[i].match(/([^0-9]+)|([0-9]+)/g);
            tempArr[i] = thisString.match(/([^0-9]+)|([0-9]+)/g);
            for (var j in tempArr[i]) {
                if (!isNaN(n = parseInt(tempArr[i][j]))) {
                    tempArr[i][j] = n;
                }
            }
        }
        tempArr.sort(function (x, y) {
            for (var i in x) {
                if (y.length < i || x[i] < y[i]) {
                    return -1; // x is longer
                }
                if (x[i] > y[i]) {
                    return 1;
                }
            }
            return 0;
        });
        for (var i in tempArr) {
            arr[i] = tempArr[i].join('');
        }
        return arr;
    }
    console.log(sortArray(nodes).join(","));

What I need is the second sorting function but with the ability to sort both alphabetically and numerically. Thanks

Answer 1

var array = [{ 
   "id" : "A20",
   "age" : "16"
}, {
   "id" : "A2",
   "age" : "12"
}, { 
   "id" : "B16",
   "age" : "45"
}];

array.sort(function(a, b) {
 var aSplit = /(\D*)(\d*)/.exec(a.id),
     bSplit = /(\D*)(\d*)/.exec(b.id);

 if( aSplit[1] !== bSplit[1] )
    return aSplit[1].localeCompare(bSplit[1]);
 else
    return aSplit[2] - bSplit[2];
});

Answer 2

Use function .sort in array, and pass has argument, a callback.

This callback receive elements to iterate, and you can compare values, if return true, switch order of elements, for ie:

arr.sort(function(a, b) {
    return parseInt(a.age) > parseInt(b.age))
};

or, if you use ecma script 6, you can use arrow function, is better, ie below:

arr.sort((a, b) => parseInt(a.age) > parseInt(b.age))

Docs here: http://www.w3schools.com/jsref/jsref_sort.asp

Answer 3

I think you can use localeCompare() to compare strings. Try this code, it should work:

nodes.sort(function(a,b){
    // console.log(a.Pos)
    // console.log(a.pinNum)
    var alc = a.id, blc = b.id;
    console.log(alc)
    return alc.localeCompare(blc);
});