[英]mapping an array of objects and sort result by string values
i hope i can find help hier.我希望我能找到帮助hier。
How can i get a full name form this array of Objects like this format: "Title" "LastName", "Name"??我怎样才能从这种格式的对象数组中获得全名:“Title”“LastName”,“Name”?
selectsUsers = [
{
column: "Name",
value: "Martin",
gqlName:"TMP_name"
},
{
column: "Lastname",
value: "Anderson",
gqlName:"TMP_lastname"
},
{
column: "Title",
value: "Sir",
gqlName:"TMP_title"
},
];
I'm using a map and join methods to return the fullname from the object's entries:我正在使用 map 和 join 方法从对象的条目中返回全名:
let pathView = this. selectsUsers
.map((item) => {
return _.get(this.obj, this.dtoName + "." + item.gqlName);
})
.join(", ");
What i go is this: "Martin, Anderson, Sir" What i want to achieve is this: "Sir Anderson, Martin"我的 go 是这样的:“Martin,Anderson,Sir” 我想要实现的是:“Sir Anderson,Martin”
i would be so thankfull if someone can help如果有人可以提供帮助,我将非常感激
You could take an object with the wanted properties and build a string from the key/value pairs.您可以使用具有所需属性的 object 并从键/值对构建字符串。
const getName = ({ Name, Lastname, Title = '' }) => `${Title}${Title && ' '}${Lastname}, ${Name}`, user = [{ column: "Name", value: "Martin" }, { column: "Lastname", value: "Anderson" }, { column: "Title", value: "Sir" }], result = getName(Object.fromEntries(user.map(({ column, value }) => [column, value]))); console.log(result);
You can use Array.prototype.reduce()
in combination with String.prototype.replace()
to do something like:您可以将Array.prototype.reduce()
与String.prototype.replace()
结合使用来执行以下操作:
const selectsUsers = [{ column: "Name", value: "Martin", }, { column: "Lastname", value: "Anderson", }, { column: "Title", value: "Sir", }, ]; const fullName = selectsUsers.reduce((outStr, {column, value}) => { return outStr.replace(`{${column}}`, value);; }, '{Title} {Lastname}, {Name}'); console.log(fullName)
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