从文件中读取行并将每个单词存储到数组（C语言）中

Question

I'm trying to make a function in C that reads a first line form file and store each word into an array of strings, than return the array or print it (I used strtok()). I've written my code but when I test it I get an error: "segmentation error" which I don't know what it means. any help??? I saw this question Segmentation fault with array of strings C i think it's similar but I still don't understand. Here's my code :

the function that reads data from file and store it into an array function is on the file: methodes.c

void lireFichier (char *file)
{
    int i = 0;
    int nbElement = 4;
    char ** tab;
    char line [1000];
    char *str[1000];
    const char s[2] = " ";
    char *token;
    FILE *myFile;

    myFile = fopen(file, "r");
    if(!myFile)
    {
        printf("could not open file");
    } else
    {
        printf("file opened\n");
        //while(fgets(line,sizeof line,myFile)!= NULL) 

        //get the fisrt line 
        fgets(line,sizeof line,myFile);

        //fprintf(stdout,"%s",line); 
        //get the fisrt word
        token = strtok(line, s);

        for(i =0; (i< nbElement) && (token != NULL); i++)
        {
            int len = strlen(token); 
            tab[i] = malloc(len);
            strncpy(tab[i], token, len-1);
            token = strtok(NULL, s);
            //printf( "%s\n", tab[i]);
        }   
    }
    fclose(myFile);
}

and here's the main.c // I pass the file as argument (in argv)

#include <stdio.h>
#include <stdlib.h>
#include "methodes.h"


int main(int argc, char *argv[])
{
    int result = 1;
    if(argc < 2)
    {
        printf("Erreur dans les arguments\n");
    } else
    {
        int idx;
        for (idx = 0; idx < argc; idx++)
        {
            printf("parameter %d value is %s\n", idx, argv[idx]);
        }

       lireFichier(argv[1]);

    }
    return 0;
}

and here's an example of the file : methodes.txt

afficher tableau
partager elements roles
nommer type profession
fin

and this is my output:

file opened
Erreur de segmentation

note: the output is in french, so the message means segmentation error thank you and sorry for all the details, i just wanted to make sure that people understand what i mean.

Answer 1

 char ** tab;

Is a uninitialised pointer to a pointer. What you need is a array of pointers.

char *tab[10];  

Instead of 10, use the size you see fit and adjust your code to include bounds checking.

Answer 2

http://www.tutorialspoint.com/cprogramming/c_array_of_pointers.htm

pointer of an array:

int *ptr[MAX];