从选择字符串将Powershell正则表达式分组

Question

I am scraping a web request response to pull information held within html code which repeats a few times so using select-string rather than match. My code looks like

$regexname = '\(\w{0,11}).{1,10}\'
$energenie.RawContent | select-string $regexname -AllMatches | % {$_.matches}

The return looks something like:

Groups : {<h2 class="ener">TV </h2>, TV}
Success : True
Captures : {<h2 class="ener">TV </h2>}
Index : 1822
Length : 33
Value : <h2 class="ener">TV </h2>

Groups : {<h2 class="ener">PS3 </h2>, PS3}
Success : True
Captures : {<h2 class="ener">PS3 </h2>}
Index : 1864
Length : 33
Value : <h2 class="ener">PS3 </h2>

I can't workout a way to grab the second element of groups eg TV or PS3 as:

$energenie.RawContent | select-string $regexname -AllMatches | % {$_.matches.groups}

Gives a strange output

Paul

Answer 1

This should work:

$energenie.RawContent | select-string $regexname -AllMatches | ForEach-Object { Write-Host $_.Matches.Groups[1].Value }

Answer 2

To get the second item in a collection, use the array index operator: [n] where n is the index from which you want a value.

For each entry in Matches , you want the second entry in the Groups property so that would be:

$MyMatches = $energenie.RawContent | select-string $regexname -AllMatches | % {$_.Matches}
$SecondGroups = $MyMatches | % {$_.Groups[1]}

To get just the captured value, use the Value property:

$MyMatches | % { $_.Groups[1].Value }