[英]How to convert fixed point (Q format) number to floating point in MATLAB
Why int16 doesn't retrieve the sign from an hex string? 为什么int16不从十六进制字符串中检索符号?
MATLAB: MATLAB:
>> single(int16(hex2dec('ffff')))
ans =
32767
ie 即
>> int16(hex2dec('ffff')) == int16(hex2dec('8fff'))
ans =
1
To put it in its general context, I want to rewrite the following numpy Python snippet code in MATLAB: 为了将其放在一般上下文中,我想在MATLAB中重写以下numpy Python代码段代码:
>>> import numpy as np
>>> i='ffff'
>>> q='3fff'
>>> i_float = np.int16(int(i,16))
>>> i_float = i_float * 2 ** -15
>>> i_float
-3.0517578125e-05
>>> q_float = np.int16(int(q,16))
>>> q_float = q_float * 2 ** -15
>>> q_float
0.499969482421875
Here's what I've got. 这就是我所拥有的。 (Yes, it seems to be more convoluted than it should be.)
(是的,它似乎比应该的要复杂得多。)
i_hex = 'ffff'
q_hex = '3fff'
i_int16 = typecast(uint16(hex2dec(i_hex)),'int16')
i_float = single(i_int16) * 2 ^ -15
q_int16 = typecast(uint16(hex2dec(q_hex)),'int16')
q_float = single(q_int16) * 2 ^ -15
Output: 输出:
i_hex = ffff
q_hex = 3fff
i_int16 = -1
i_float = -3.05175781250000e-05
q_int16 = 16383
q_float = 0.499969482421875
hex2dec
converts hex to a double, so I cast it to a uint16
so as to preserve the sign bit (which hex2dec
refuses to do). hex2dec
将hex2dec
转换为double,因此我将其转换为uint16
,以便保留符号位( hex2dec
拒绝这样做)。 Then I typecast
the result to a signed int16
. 然后,将结果
typecast
为带符号的int16
。 This just takes the bits of the uint16
and interprets them as an int16
. 这只是获取
uint16
的位并将其解释为int16
。 Then cast it to a single
and bitshift. 然后将其强制转换为
single
移位。
Note: I used format long
to see as many decimal places as I could. 注意:我使用
format long
来查看尽可能多的小数位。
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