Long.parseLong提供NumberFormatException

Question

My issue is that

checksum = Long.parseLong("-986.9"); 

is giving NumberFormatException. Isn't this a parsible long?

Answer 1

A Long is not a decimal. Use Double and convert :

Double.parseDouble("-986.9").longValue(); 

Answer 2

No it isn't. A long is a numeric integer type, and your number has a decimal point.

You want a double here (ie Double.parseDouble() ).

Answer 3

long is an integer data type, -986.9 is not an integer. The below works for me.

long checksum = Long.parseLong("-986");
    System.out.println(checksum);
    double checksum2 = Double.parseDouble("-986.6");
    System.out.println(checksum2);

Answer 4

使用双Double.parseDouble(var) ，使用方法Double.parseDouble(var)