java：Long.parseLong（s，16）和Long.toHexString（l）不反转？

Question

I get this but yet I don't get it:

package com.example.bugs;

public class ParseLongTest {
    public static void main(String[] args) {
        long l = -1;
        String s = Long.toHexString(l);
        System.out.println(s);
        long l2 = Long.parseLong(s, 16);
    }   
}

This fails with the following:

ffffffffffffffff
Exception in thread "main" java.lang.NumberFormatException: For input string: "ffffffffffffffff"
    at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
    at java.lang.Long.parseLong(Long.java:410)
    at java.lang.Long.parseLong(Long.java:468)
    at com.example.bugs.ParseLongTest.main(ParseLongTest.java:8)

presumably because if you literally interpreted 0xffffffffffffffffL, it would not fit in the Long number space, which is signed.

But why does Long.toHexString() produce a string that cannot be parsed by Long.parseLong(), and how do I work around this? (I need a way of getting long values to their hex string representation, and back again)

Answer 1

Long.parseLong(String s, int radix) doesn't understand two's complement. For negative number it expects minus sign. As bestsss already mentioned you should use Long.toString(long l, int radix) to make hex string compatible with this parsing method.

Answer 2

这是一个已知的错误，它在1.8中已修复，请参阅http://bugs.sun.com/bugdatabase/view_bug.do?bug_id=4215269

Answer 3

如果Java 1.8不是选项UnsignedLongs.parseUnsignedLong(String s, int radix)可以使用guava的UnsignedLongs.parseUnsignedLong(String s, int radix) 。