在Bash的字符串输出中查找并仅回显日期（带有格式）

Question

I am trying to get the date "+%a %b %d %R:%S %Y" in bash.

here's the sample command and output

$ xscreensaver-command --time XScreenSaver 5.32: screen non-blanked since Thu Oct 29 12:15:05 2015 (hacks: #184, #60)

I am trying to get the the value Thu Oct 29 12:15:05 2015 on the string.

How can I achieve this?

Answer 1

Try to append with GNU grep:

2>&1 | grep -Po 'since \K.*(?= \()'

Output:

Thu Oct 29 12:15:05 2015