[英]bash echo time date format
I have tested the format I need however I am unable to get the echo output, try put the quote around the different position.我已经测试了我需要的格式,但是我无法获得回声输出,尝试将引号放在不同的位置。
[root@]# date '+%B %V %T.%3N:'
July 29 21:01:24.766:
echo 'date ’+%B %V %T.%3N:’ %LINK-3-UPDOWN: Interface Port-channel1, changed state to up'
expected output预期产出
July 29 21:01:24.766: %LINK-3-UPDOWN: Interface Port-channel1, changed state to up'
You can do:你可以做:
tm=$(date '+%B %V %T.%3N:')
echo "${tm} %LINK-3-UPDOWN: Interface Port-channel1, changed state to up"
Prints:印刷:
July 29 09:22:23.3N: %LINK-3-UPDOWN: Interface Port-channel1, changed state to up
Note the double "
vs single '
. Only strings in double quotes are interpolated in the shell:注意双"
与单'
。只有双引号中的字符串会在 shell 中插入:
bash-5.1$ s1='hello'
bash-5.1$ s2='there'
bash-5.1$ echo "${s1} ${s2}"
hello there
vs:对比:
bash-5.1$ echo '${s1} ${s2}'
${s1} ${s2}
If you want the whole thing in one line:如果你想在一行中完成整个事情:
echo "$(date '+%B %V %T.%3N:') %LINK-3-UPDOWN: Interface Port-channel1, changed state to up"
Or modify your date
format string:或修改您的date
格式字符串:
date '+%B %V %T.%3N: %%LINK-3-UPDOWN: Interface Port-channel1, changed state to up'
You don't actually need echo
.你实际上并不需要echo
。 Let date
write everything:让date
写一切:
$ date '+%B %V %T.%3N %%LINK-3-UPDOWN: Interface Port-channel1, changed state to up'
July 29 09:34:15.874 %LINK-3-UPDOWN: Interface Port-channel1, changed state to up
Technically, you don't even need date
, if you are willing to sacrifice the fraction of a second in the timestamp:从技术上讲,如果您愿意牺牲时间戳中的几分之一秒,您甚至不需要date
:
$ printf '%(%B %V %T)T %s\n' -1 "%LINK-3-UPDOWN: Interface Port-channel1, changed state to up"
July 29 09:36:40 %LINK-3-UPDOWN: Interface Port-channel1, changed state to up
( bash
doesn't support %N
in its implementation of printf
. %(...)T
formats an integer number of seconds according to ...
, with -1
representing the current time.) ( bash
在它的printf
实现中不支持%N
。 %(...)T
根据...
格式化整数秒, -1
表示当前时间。)
Characters inside single quotes are a static string, always.单引号内的字符始终是静态字符串。 If you want to execute a shell command, you need a command substitution, usually inside double quotes:如果要执行 shell 命令,则需要命令替换,通常在双引号内:
echo "$(date ’+%B %V %T.%3N:’) %LINK-3-UPDOWN: Interface Port-channel1, changed state to up"
However, that's basically just a useless use of echo
.但是,这基本上只是echo
的无用使用。
date ’+%B %V %T.%3N: %%LINK-3-UPDOWN: Interface Port-channel1, changed state to up'
Notice how you need to double any literal %
characters in the date
format string.请注意您需要如何将date
格式字符串中的任何文字%
字符加倍。
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