[英]bash echo time date format
我已經測試了我需要的格式,但是我無法獲得回聲輸出,嘗試將引號放在不同的位置。
[root@]# date '+%B %V %T.%3N:'
July 29 21:01:24.766:
echo 'date ’+%B %V %T.%3N:’ %LINK-3-UPDOWN: Interface Port-channel1, changed state to up'
預期產出
July 29 21:01:24.766: %LINK-3-UPDOWN: Interface Port-channel1, changed state to up'
你可以做:
tm=$(date '+%B %V %T.%3N:')
echo "${tm} %LINK-3-UPDOWN: Interface Port-channel1, changed state to up"
印刷:
July 29 09:22:23.3N: %LINK-3-UPDOWN: Interface Port-channel1, changed state to up
注意雙"
與單'
。只有雙引號中的字符串會在 shell 中插入:
bash-5.1$ s1='hello'
bash-5.1$ s2='there'
bash-5.1$ echo "${s1} ${s2}"
hello there
對比:
bash-5.1$ echo '${s1} ${s2}'
${s1} ${s2}
如果你想在一行中完成整個事情:
echo "$(date '+%B %V %T.%3N:') %LINK-3-UPDOWN: Interface Port-channel1, changed state to up"
或修改您的date
格式字符串:
date '+%B %V %T.%3N: %%LINK-3-UPDOWN: Interface Port-channel1, changed state to up'
你實際上並不需要echo
。 讓date
寫一切:
$ date '+%B %V %T.%3N %%LINK-3-UPDOWN: Interface Port-channel1, changed state to up'
July 29 09:34:15.874 %LINK-3-UPDOWN: Interface Port-channel1, changed state to up
從技術上講,如果您願意犧牲時間戳中的幾分之一秒,您甚至不需要date
:
$ printf '%(%B %V %T)T %s\n' -1 "%LINK-3-UPDOWN: Interface Port-channel1, changed state to up"
July 29 09:36:40 %LINK-3-UPDOWN: Interface Port-channel1, changed state to up
( bash
在它的printf
實現中不支持%N
。 %(...)T
根據...
格式化整數秒, -1
表示當前時間。)
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