Python字符串函数中的数字总和

Question

My function needs to take in a sentence and return the sum of the numbers inside. 我的函数需要接受一个句子并返回内部数字的总和。 Any advice? 有什么建议吗？

def sumOfDigits(sentence):
    sumof=0
    for x in sentence:
        if sentence.isdigit(x)== True:
            sumof+=int(x)
    return sumof

Answer 1

Replace this: 替换为：

if sentence.isdigit(x)== True:

to: 至：

if x.isdigit():

examples: 例子：

 >>> "1".isdigit()
 True
 >>> "a".isdigit()
 False

your code should be like: 您的代码应类似于：

def sumOfDigits(sentence):
    sumof=0
    for x in sentence:
        if x.isdigit():
            sumof+=int(x)
    return sumof

Some pythonic ways: 一些Python方式：

Using List Comprehension: 使用列表推导：

>>> def sumof(sentence):
...     return sum(int(x) for x in sentence if x.isdigit())
... 
>>> sumof("hello123wor6ld")
12

Using Filter, map: 使用过滤器，映射：

>>> def sumof(sentence):
...     return sum(map(int, filter(str.isdigit, sentence)))
... 
>>> sumof("hello123wor6ld")
12

Using Regular expression, extraction all digit: 使用正则表达式提取所有数字：

>>> import re
>>> def sumof(sentence):
...     return sum(map(int, re.findall("\d",sentence)))
... 
>>> sumof("hello123wor6ld")
12

Answer 2

You have to ask if x is a digit. 您必须询问x是否为数字。

def sumOfDigits(sentence):
    sumof=0
    for x in sentence:
        if x.isdigit()== True:
            sumof+=int(x)
    return sumof