检查字符串是否为九位数，然后在 python 中退出 function

Question

I have a function in python that returns different output of strings (Text). And I have different parts that I should check for the string and if the string is of nine digits or contains 9 digits then I need to perform in the function to exit the function at the point I am newbie at python and I don't know how to exit the function at specific point if a criteria is achieved. For example

s = 'oodf 191876320x sd'
print(any(char.isdigit() for char in s))

This checks if the string has digits. I need to add another criteria to make sure there are adjacent 9 numbers. and if True , then exit the function at the point.

The code that I am working on is to read number from image (with three different cases of manipulation) This is my try and I welcome any ideas

import pytesseract, cv2, re

def readNumber(img):
    img = cv2.imread(img)
    gry = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY)
    txt = pytesseract.image_to_string(gry)
    if bool(re.search(r'\d{9}', txt)):
        return re.findall('(\d{9})\D', txt)[0]
    blur = cv2.GaussianBlur(img, (3,3), 0)
    txt = pytesseract.image_to_string(blur)
    if bool(re.search(r'\d{9}', txt)):
        return re.findall('(\d{9})\D', txt)[0]
    thr = cv2.adaptiveThreshold(gry, 255, cv2.ADAPTIVE_THRESH_GAUSSIAN_C, cv2.THRESH_BINARY, 51, 4)
    txt = pytesseract.image_to_string(thr, config="digits")
    if bool(re.search(r'\d{9}', txt)):
        return re.findall('(\d{9})\D', txt)[0]
    '''
    
    try:
        txt = pytesseract.image_to_string(gry)
        #txt  = re.findall('(\d{9})\D', txt)[0]
    except:
        thr = cv2.adaptiveThreshold(gry, 255, cv2.ADAPTIVE_THRESH_GAUSSIAN_C, cv2.THRESH_BINARY, 51, 4)
        txt = pytesseract.image_to_string(thr, config="digits")
        #txt  = re.findall('(\d{9})\D', txt)[0]

    return txt
'''
    
# M5Pr5         191876320
# RWgrP         202131290
# 6pVH4         193832560
print(readNumber('M5Pr5.png'))
print(readNumber('RWgrP.png'))
print(readNumber('6pVH4.png'))

The related question is on that link Read text below barcode pytesseract python

Answer 1

You can simply return from the function when the condition is satisfied:

# Suppose the string is stored in text variable

if len(text) == 9:
    return

Answer 2

use regex. The below regex will match given that the string contains 9 adjacent digits.

\d{9,}

Answer 3

to exit a function do you mean to return back from where it was called?

if so then use

if len(stringVarible)==9:
   return