如何从文本文件python中的数字列表中找到平均值

Question

Inside the the text file there is a list of name along side a number which denotes their score in this case. is there a way to figure out the average of all the numbers in the text file.

Code:

print("average calculator")
option = input("option: ")
option_class = input("class: ")
one = "1.txt"
if option.lower() == 'avg' and option_class == '1':
    name = input("name: ")

    with open(one) as f:
        the_list = [int(l.strip().split()[-1]) for l in f if name in l]

        b = sum(the_list)
        length = len(the_list)
        avg = float(b) / length if length else 0
        print (name,"Average is: ", avg)

The section where the code asks the user their name, here it finds all the numbers in the text file that are next to the name, however I am trying to Remove this aspect and allow the code to recognise all the numbers in the file...

Text File:

Matt 3
Jhon 4
Alex 6

From these numbers, [3,4,6] the average should be worked out, NB: the text file can be appended, more names and scores can be added.

TIA!

Answer 1

try the pandas library.

something of the lines:

import pandas as pd
df = pd.read_csv('filename.txt', delimiter=' ')
df['Column name'].mean()

it has functionality to filter and group data easily, and is much more useful for this kind of task than writing your own code. I working with files 100,000 lines +, and can read, group, filter outliers in each group and compute statistics in about 4 lines of code.

http://pandas.pydata.org/

Answer 2

List comprehension:

the_list = [int(l.strip().split()[-1]) for l in f if name in l]

Equivalent:

with open(one) as f:
    the_list = []   # creating empty list or (array)
    for l in f:     # treversing over the lines in file
        if name in l:  # if input name is in the line do next line
            the_list.append(int(l.strip().split()[-1])) # adding element to list
        else:   # if input name is not in line ignore the line dont use the score
            pass