如何找到文本文件中字符串中包含的列表中数字的平均值？

Question

my.txt:

AAAAA -- [4, 2, 1, 2, 4, 2, 4, 4, 5, 2, 2, 1, 5, 2, 4, 3, 1, 1, 3, 3, 5]

BBB -- [5, 2, 1, 2, 4, 5, 4, 4, 1, 2, 2, 2, 4, 4, 4, 3, 1, 2, 3, 3, 2]

K -- [4, 1, 2, 1, 2, 1, 2, 5, 1, 1, 1, 1, 4, 2, 2, 1, 5, 1, 3, 4, 1]

How can I make a code that outputs this: (averages of all numbers in each string)

AAAAA,2.857142857142857

BBB,2.857142857142857

K,2.142857142857143

Note: the code has to work for any other text files contains different numbers/sizes of lists, so I can't just do something like str = "AAAAA -- [4, 2, 1, 2, 4, 2, 4, 4, 5, 2, 2, 1, 5, 2, 4, 3, 1, 1, 3, 3, 5]" and then find the average of this

the_file = "1.txt"

fileRef = open(the_file,"r")      
localList_ofstrings=[]            
for line in fileRef:
    string = line[0:len(line)-1]
    localList_ofstrings.append(string)
    print(string)

Answer 1

The entries in the file are formatted exactly as ordinary Python dictionaries, so you could treat them as such:

import ast

data = {}
with open(the_file) as f:
    for line in f:
        key, value = line.split('--')
        data[key.strip()] = ast.literal_eval(value.strip())  # parse data as Python list literal

Now data will be a dictionary like this:

{
    'AAA': [4, 2, 1, 2, 4, 2, 4, 4, 5, 2, 2, 1, 5, 2, 4, 3, 1, 1, 3, 3, 5],
    ...
}

I hope this data structure will help you calculate the means and write them back to the file

Answer 2

This is my solution:

import re
from os.path import exists


def calculate(path: str):
    pattern_digit = re.compile(r"\d")
    pattern_alpha = re.compile(r"[A-Za-z]")
    digits = []
    alphas = []
    if exists(path):
     try:
        with open(path) as file:
            string = file.read()
        listed_str = string.splitlines()

        for emp_str in listed_str:
            if emp_str == '':
                listed_str.remove(emp_str)

        for number in range(len(listed_str)):
            digits.append(sum([int(n) for n in pattern_digit.findall(listed_str[number])]))

        for alphabet in range(len(listed_str)):      
          alphas.append(''.join(pattern_alpha.findall(listed_str[alphabet])))
     except FileNotFoundError:
       return "No such file or directory found"


    for p in range(len(alphas)):
        print(f"{alphas[p]}---- {digits[p] / len(digits)}")

I know It's a bit complicated, but I guarantee It Will work as you want.

Answer 3

Okay so I have a pretty simple solution.

with open('file.txt','r') as f:

    for line in f.readlines():
        try:
            name, l = tuple(line.split('--'))
        except ValueError:
            continue
        name = str.strip(name)
        l = str.strip(l,' []\n')
        l = list(map(int, l.split(',')))
        print("{},{}".format(name, sum(l)/len(l)))

So allow me to explain this to you. All I did is read the file, then split them with -- delimiter, then strip the white space in name and then, striped white space, new line character and third bracket. Then I split the list elements by , then mapped them to int using map function. If you are not familiar with map then you can also use list comprehension. Then, I simply calculated the average and print it.

If you are not familiar with map , just replace the line with l = [int(i) for i in l.split(',')] and it should work just fine.
Hope it helps you. Cheers:)