int（）参数必须是字符串，类似字节的对象或数字，而不是“列表”

Question

I am trying to plot a graph using matplotlib.pyplot in Python but getting an error:

int() argument must be a string, a bytes-like object or a number, not 'list'

in the second-to-last line.

Here is the code:

import numpy as np
import random
import matplotlib.pyplot as plt

#constants
mUn0 = 1350
Vcat = 18000000
n = 2 * pow(10,16)
e = 1.6 * pow(10,-19)

#variable
E = 1000
d = []
f = []

for i in range(1,E):
    j = log(n*e*mUn0) + log(i) - 0.5 * log(1+pow((mUn0*i/Vcat),2))
    f.append(j)
    d.append(log(i))
plt.xlabel('E')
plt.ylabel('V')
plt.subplot(2,1,2)
plt.subplot(f,d,'bo')
plt.show()

Thank you

Answer 1

pyplot.subplot() requires subplot(nrows, ncols, plot_number) , all three options are integers.

Matplotlib is trying to cast your f and d lists to integer type and failing.

Answer 2

Just a couple of small issues. You have to use plt.plot() to plot, and you can't just use log , you need np.log() or to import the math module and then use math.log() . I noted the lines I changed with #FIXED

import numpy as np
import random
import matplotlib.pyplot as plt

#constants
mUn0 = 1350
Vcat = 18000000
n = 2 * pow(10,16)
e = 1.6 * pow(10,-19)

#variable
E = 1000
d = []
f = []

for i in range(1,E):
    j = np.log(n*e*mUn0) + np.log(i) - 0.5 * np.log(1+pow((mUn0*i/Vcat),2))  #FIXED
    f.append(j)
    d.append(np.log(i)) #FIXED
plt.xlabel('E')
plt.ylabel('V')
plt.subplot(2,1,2) #not needed, but maybe a holdover from full code
plt.plot(f,d,'bo') #FIXED
plt.show()

That takes care of the syntax errors. Using a subplot works with one plot but you don't need it, so I don't know what type of logic error that is (do you want two plots?)