如何编写mysql查询来跟踪今天的记录

Question

i need to track opened,unopened and delivered emails by date. suppose i sent 5 emails yesterday but nothing opened yesterday and today again i sent another 5 emails so the total emails sent today =5. opened today =3(including yesterday's 2 and today's 1 email opened .still unopened 7 which is correct). But i need to display

today's unopened mails count = today's sent mails- today's sent emails opened

Here is my db structure

ID ||| Email ||| Event |||  date**

1 ||| AAA  ||| Sent ||| 04-11-2015

2 ||| BBB  ||| Sent ||| 04-11-2015

3 ||| CCC  ||| Sent |||  04-11-2015

4 ||| DDD  ||| Sent ||| 04-11-2015

5 ||| EEE  ||| Sent||| 04-11-2015

6 ||| FFF  ||| Sent ||| 05-11-2015

7 ||| GGG  ||| Sent ||| 05-11-2015

8 ||| HHH  ||| Sent ||| 05-11-2015

9 ||| III  ||| Sent ||| 05-11-2015

I0 ||| JJJ  ||| Sent ||| 05-11-2015

11 ||| AAA  ||| Open ||| 05-11-2015

12 ||| BBB  ||| Open ||| 05-11-2015

13 ||| FFF  ||| Open ||| 05-11-2015

Answer 1

Use MySQL str_to_date or curdate :-

Select Email,
    ((select count(*) from table
    where str_to_date(date,'%d-%m-%Y')=curdate() and Event='Sent')
    -
    (select count(*) from table 
    where str_to_date(date,'%d-%m-%Y')=curdate() and Event='Open')) as unopened 
From table limit 1

Answer 2

Today i sent these emails

FFF ||| Sent ||| 05-11-2015

GGG ||| Sent ||| 05-11-2015

HHH ||| Sent ||| 05-11-2015

III ||| Sent ||| 05-11-2015

JJJ ||| Sent ||| 05-11-2015

On these emails opened only 1

FFF ||| Open ||| 05-11-2015

So unopened 4 emails.

ofcourse these are opened today but these mails sent yesterday.

AAA ||| Open ||| 05-11-2015

BBB ||| Open ||| 05-11-2015

I want todays unopened= (today's sent)- (today's sent opened)

unopened = 5-1(today's sent email opened)

so total i will get 4.

Answer 3

要使用MySQL获取今天的记录，您可以尝试以下操作：

SELECT * FROM tbl_name WHERE date > DATE_SUB(NOW(), INTERVAL 1 DAY);